Derive a relation for force in term of change in momentum
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Answer:
F = m×a
F = m×(v-u)/t
F = mv-mu/t
F = p2-p1/t
F = ∆p/t
#Secretgirl✌️
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Explanation:
F=ma
F=m∆v/∆t
F×∆t=m∆v. (p=m∆v)
F×∆t=∆p
F=∆p/∆t
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