derive all the components of a projectile fired at an angle with the ground
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An object is thrown at an angle θ from the horizontal.
Equation of trajectory
We will divide the projectile motion into 2 different linear motion in x and y axes.
Time = T
Velocity in x axis = v cos(θ)
Velocity in y axis = v sin(θ)
Distance in x Axis =x= [v cos(θ)] × T ....(i)
Distance in y Axis
y = v sin(θ) × T - ½gT² ______(ii)
Putting value of T in eq.(ii)
y = x × v sin(θ)/ v cos(θ) - ½g{x/vcos(θ)}²
y = x tan(θ) - gx²/2u²cos²(θ).
The derived equation is similar to a parabolic equation
y = ax - bx².
So the trajectory of a projectile is a Parabola.
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