Derive all the expressions for joules's law by using ohms law?
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) Derive an expression for Joule's law of heating.
(b) Give two examples for applications of heating effect of electric current.
(c) 100 J of heat is produced each second in a 4Ω resistor. Find the potential difference across the resistor.
P = VI
H = P × t = Vlt
But V = IR (ohm's law)
∴ H = I2Rt
(b) (a) Electric fuse
(b) Electric water heater
(c) H = 100J , R = 4 Ω , t = 1 sec .
H = I2Rt
I2 = H / R
Now, V = IR
V = 5 × 4
V = 20 V .
Explanation:
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