Question

Derive all the expressions for joules's law by using ohms law?

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Answer 1

Answer:

) Derive an expression for Joule's law of heating.

(b) Give two examples for applications of heating effect of electric current.

(c) 100 J of heat is produced each second in a 4Ω resistor. Find the potential difference across the resistor.

P = VI

H = P × t = Vlt

But V = IR (ohm's law)

∴ H = I2Rt

(b) (a) Electric fuse

(b) Electric water heater

(c) H = 100J , R = 4 Ω , t = 1 sec .

H = I2Rt

I2 = H / R

Now, V = IR

V = 5 × 4

V = 20 V .

Explanation:

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