Question

Derive an equation for the path of a projectile fired parallel to horizontal.
CLASS - XI PHYSICS (Kinematics)

Answer 1

in horizontal projectile velocity in x-axis is always constant due to absence of acceleration in x -axis .
use kinematic equation, for x-axis
S =ut + 1/a t^2
a =0 in x - axis

hence,
X =ut + 0
X =ut -------(1)

now for y-axis
S =ut + 1/2 at^2

u= 0 in y -axis and a = -g

Y = - g/2 t^2 -----------(2)

from equation (1) and (2)
Y = -g/2 {X/u}^2

Y = -gX^2/2u^2

you can see that the path of projectile is parabolic .