Question

Derive an equation for the path of a projectile fired parallel to horizontal​

Answer 1

let the initial velocity be u m/s. angle of projection = 0 initial component of velocity in vertical direction = 0 horizontal

Answer 2

Answer:

in horizontal projected particle ,

acceleration in horizontal =0

acceleration in vertical = -g

let initial velocity in horizontal =U

★ velocity doesn't change in horizontal

★ velocity of vertical may change

now,

kinematics equation for horizontal

X = Uxt + 1/axt²

X = Uxt +0

X = Ut --------(1)

kinematics equation for vertical

Y = Uyt + 1/2ayt²

Y = 0 -1/2gt²

put equation here

Y = -1/2g(X/U)²

Y = -gX²/2U²