Question

derive an explanation for acceleration due to gravity​

Answer 1

Answer:

Explanation:

We get, ⇒g=GM(R−d)R3. Therefore the expression of acceleration due to gravity of a body at a depth d from the surface of earth is GM(R−d)R3. Here, we can understand that the acceleration of a body due to gravity inside earth decreases as we go from the surface to the centre of earth. At centre g=0.

Answer 2

Answer:

Formula of Acceleration due to Gravity

Force acting on a body due to gravity is given by, f = mg

Where f is the force acting on the body, g is the acceleration due to gravity, m is mass of the body.

According to the universal law of gravitation, f = GmM/(r+h)2

Where,

f = force between two bodies,

G = universal gravitational constant (6.67×10-11 Nm2/kg2)

m = mass of the object,

M = mass of the earth,

r = radius of the earth.

h = height at which the body is from the surface of the earth.

As the height (h) is negligibly small compared to the radius of the earth we re-frame the equation as follows,

f = GmM/r2

Now equating both the expressions,

mg = GmM/r2

⇒ g = GM/r2

Therefore, the formula of acceleration due to gravity is given by, g = GM/r2

Note: It depends on the mass and radius of the earth.

Explanation:

I hope it is helpful....