Question

Derive an expresion for specific heat capacity of water.​

Answer 1

Answer:

(i) Mass of empty calorimeter(with stirrer) = m1 gm.

(ii) Mass of the metal piece = M gm.

(iii) Mass of calorimeter and water = m2 gm.

(iv) Initial temperature of water = t10C

(v) Temperature of hot solid (metal piece) = t20C

(vi) Final temperature of the mixture = t0C

(vii) Specific heat of calorimeter = 0.4 J gm/0C

Answer 2

Answer:

Calculations : Let's' J/ gm/0C be the specific heat of the solid. Now, heat given out by hot solid = Heat taken up by calorimeter + Heat taken up by water. From this heat equation, 's' can be calculated where all other values are known.