Question

)Derive an expression for acceleration due to gravity.(ii) A particle is thrown up vertically with a velocity of 50 m/s. (a)What will be its velocity atthe highest point of the journey?(b)How high would the particle rise?(c)What time would it take to reach the highest point? [ Take g= 10 m/s2]

Answer 1

Velocity at highest point=0m/s

v=0

According to free fall

v^2-u^2=2gh

0-50*50=1×10×h

0-2500=10h

-2500=10h

h=250m(height cannot be negative)

v=u+gt

0=50+10*t

-50=10t

t=5sec (time cannot be negative)