Question

derive an expression for acceleration for an object falling freely. pls answer fast.

Answer 1

s = 0 + (1/2)g(T/2)²

s = (1/2)(g/4)T²

Substituting the value of T²

s = (1/2)(g/4)(2h/g)

s = h/4

or h=4s

According to equation of motion

s = ut + (1/2)at²

h = 0 + (1/2)gT²

T² = 2h/g

T=root2h/g