Question

derive an expression for angular momentum​

Answer 1

Answer:

Angular Momentum = (moment of inertia)(angular velocity)

L = I ω I\omega Iω

L = angular momentum (kg. m 2 / s m^{2}/s m2/s.

ω = angular velocity (radians/s)

L = I ω

L = ( 1 2 M R 2 ) ω (\frac{1}{2}MR^{2})\omega (21MR2)ω

A basketball spinning on the finger of an athlete has angular velocity ω = 120.0 rad/s. ...

L = I ω