Question

Derive an expression for apparent weight of a person in a lift when the lift is moving downward with an acceleration ‘a’.


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Answer 1

Answer:

Apparent weight of a person in lift will be m(g+a) while moving upwards whereas it will be m(g−a) while moving downwards.

Explanation:

Here the +ve and -ve of g and a will be understand by the given image...

In these type of questions if a is opp. to g then it will -ve and when a is along g then it will be +ve

Hint:- But remember while doing these questions g>a will always matter therefore(mg-ma)and (mg+ma)