Physics, asked by PragyaTbia, 1 year ago

Derive an expression for binding energy of a body at rest on the earth's surface.

Answers

Answered by abhi178
69
consider a body of mass ‘ m ’ which is rest on the surface of the earth. as it is in rest so, it cannot possess kinetic energy e.g., K.E = 0

because body is in the gravitational field of the earth so, gravitational potential at a point the surface of the earth is given by V=-\frac{GM}{R}

now, potential energy = gravitational potential × mass of body
= -\frac{GMm}{R}
now, total mechanical energy is T.E=K.E+P.E
so, T.E=-\frac{GMm}{R}
here negative sign indicates that the body is bound to the earth by attractive force and cannot leave it on its own. To move the body to infinity , we have to supply energy from outside the body - planet system. this energy is known as binding energy.
so, binding energy E_r=\frac{GMm}{R}
Answered by krishnasri99
11

Answer:

previous ans is absolutely correct

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