Derive an expression for conductivity in case of srmiconductor
Answers
Answer:
,
,i.e. I = Ie + Ih
,i.e. I = Ie + Ih As we know that
,i.e. I = Ie + Ih As we know thatI = ne A Vd
,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A Ve
,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A VeAnd Ih = nh e A Vh
,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A VeAnd Ih = nh e A VhI = ne e A Ve + nh e A Vh
,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A VeAnd Ih = nh e A VhI = ne e A Ve + nh e A VhI = eA[ne Ve + nh vh]
,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A VeAnd Ih = nh e A VhI = ne e A Ve + nh e A VhI = eA[ne Ve + nh vh] I/A = e[ne Ve + nh vh] (2)
,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A VeAnd Ih = nh e A VhI = ne e A Ve + nh e A VhI = eA[ne Ve + nh vh] I/A = e[ne Ve + nh vh] (2)As we know that
,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A VeAnd Ih = nh e A VhI = ne e A Ve + nh e A VhI = eA[ne Ve + nh vh] I/A = e[ne Ve + nh vh] (2)As we know thatE = V/l (in magnitude)
,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A VeAnd Ih = nh e A VhI = ne e A Ve + nh e A VhI = eA[ne Ve + nh vh] I/A = e[ne Ve + nh vh] (2)As we know thatE = V/l (in magnitude)Also, R = ρl/A
,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A VeAnd Ih = nh e A VhI = ne e A Ve + nh e A VhI = eA[ne Ve + nh vh] I/A = e[ne Ve + nh vh] (2)As we know thatE = V/l (in magnitude)Also, R = ρl/AOr ρ = RA/l
,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A VeAnd Ih = nh e A VhI = ne e A Ve + nh e A VhI = eA[ne Ve + nh vh] I/A = e[ne Ve + nh vh] (2)As we know thatE = V/l (in magnitude)Also, R = ρl/AOr ρ = RA/lWhere ρ is resistivity and R is resistance
,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A VeAnd Ih = nh e A VhI = ne e A Ve + nh e A VhI = eA[ne Ve + nh vh] I/A = e[ne Ve + nh vh] (2)As we know thatE = V/l (in magnitude)Also, R = ρl/AOr ρ = RA/lWhere ρ is resistivity and R is resistanceOr E/ρ = (V/l)/ ρ
,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A VeAnd Ih = nh e A VhI = ne e A Ve + nh e A VhI = eA[ne Ve + nh vh] I/A = e[ne Ve + nh vh] (2)As we know thatE = V/l (in magnitude)Also, R = ρl/AOr ρ = RA/lWhere ρ is resistivity and R is resistanceOr E/ρ = (V/l)/ ρOr E/ρ = (V/l)l/ RA
,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A VeAnd Ih = nh e A VhI = ne e A Ve + nh e A VhI = eA[ne Ve + nh vh] I/A = e[ne Ve + nh vh] (2)As we know thatE = V/l (in magnitude)Also, R = ρl/AOr ρ = RA/lWhere ρ is resistivity and R is resistanceOr E/ρ = (V/l)/ ρOr E/ρ = (V/l)l/ RAE/ρ = (V/RA)
,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A VeAnd Ih = nh e A VhI = ne e A Ve + nh e A VhI = eA[ne Ve + nh vh] I/A = e[ne Ve + nh vh] (2)As we know thatE = V/l (in magnitude)Also, R = ρl/AOr ρ = RA/lWhere ρ is resistivity and R is resistanceOr E/ρ = (V/l)/ ρOr E/ρ = (V/l)l/ RAE/ρ = (V/RA)E/ρ = I/A
(3)
Put (3) in (2) we get,
Put (3) in (2) we get,E/ρ = e[ne Ve + nh vh]
Put (3) in (2) we get,E/ρ = e[ne Ve + nh vh]I/ò ρ = e / E[ne Ve + nh vh]
Put (3) in (2) we get,E/ρ = e[ne Ve + nh vh]I/ò ρ = e / E[ne Ve + nh vh]σ = e [ne Ve/E + nh vh/E]
(σ = Conductivity)
Here, mobility (m) = Drift vel./ Electric field
Here, mobility (m) = Drift vel./ Electric fieldσ = e [ne me + nh mh]
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