Question

Derive an expression for conductivity in case of srmiconductor

Answer 1

Answer:

,

,i.e. I = Ie + Ih

,i.e. I = Ie + Ih As we know that

,i.e. I = Ie + Ih As we know thatI = ne A Vd

,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A Ve

,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A VeAnd Ih = nh e A Vh

,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A VeAnd Ih = nh e A VhI = ne e A Ve + nh e A Vh

,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A VeAnd Ih = nh e A VhI = ne e A Ve + nh e A VhI = eA[ne Ve + nh vh]

,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A VeAnd Ih = nh e A VhI = ne e A Ve + nh e A VhI = eA[ne Ve + nh vh] I/A = e[ne Ve + nh vh] (2)

,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A VeAnd Ih = nh e A VhI = ne e A Ve + nh e A VhI = eA[ne Ve + nh vh] I/A = e[ne Ve + nh vh] (2)As we know that

,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A VeAnd Ih = nh e A VhI = ne e A Ve + nh e A VhI = eA[ne Ve + nh vh] I/A = e[ne Ve + nh vh] (2)As we know thatE = V/l (in magnitude)

,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A VeAnd Ih = nh e A VhI = ne e A Ve + nh e A VhI = eA[ne Ve + nh vh] I/A = e[ne Ve + nh vh] (2)As we know thatE = V/l (in magnitude)Also, R = ρl/A

,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A VeAnd Ih = nh e A VhI = ne e A Ve + nh e A VhI = eA[ne Ve + nh vh] I/A = e[ne Ve + nh vh] (2)As we know thatE = V/l (in magnitude)Also, R = ρl/AOr ρ = RA/l

,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A VeAnd Ih = nh e A VhI = ne e A Ve + nh e A VhI = eA[ne Ve + nh vh] I/A = e[ne Ve + nh vh] (2)As we know thatE = V/l (in magnitude)Also, R = ρl/AOr ρ = RA/lWhere ρ is resistivity and R is resistance

,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A VeAnd Ih = nh e A VhI = ne e A Ve + nh e A VhI = eA[ne Ve + nh vh] I/A = e[ne Ve + nh vh] (2)As we know thatE = V/l (in magnitude)Also, R = ρl/AOr ρ = RA/lWhere ρ is resistivity and R is resistanceOr E/ρ = (V/l)/ ρ

,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A VeAnd Ih = nh e A VhI = ne e A Ve + nh e A VhI = eA[ne Ve + nh vh] I/A = e[ne Ve + nh vh] (2)As we know thatE = V/l (in magnitude)Also, R = ρl/AOr ρ = RA/lWhere ρ is resistivity and R is resistanceOr E/ρ = (V/l)/ ρOr E/ρ = (V/l)l/ RA

,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A VeAnd Ih = nh e A VhI = ne e A Ve + nh e A VhI = eA[ne Ve + nh vh] I/A = e[ne Ve + nh vh] (2)As we know thatE = V/l (in magnitude)Also, R = ρl/AOr ρ = RA/lWhere ρ is resistivity and R is resistanceOr E/ρ = (V/l)/ ρOr E/ρ = (V/l)l/ RAE/ρ = (V/RA)

,i.e. I = Ie + Ih As we know thatI = ne A Vd\Ie = ne e A VeAnd Ih = nh e A VhI = ne e A Ve + nh e A VhI = eA[ne Ve + nh vh] I/A = e[ne Ve + nh vh] (2)As we know thatE = V/l (in magnitude)Also, R = ρl/AOr ρ = RA/lWhere ρ is resistivity and R is resistanceOr E/ρ = (V/l)/ ρOr E/ρ = (V/l)l/ RAE/ρ = (V/RA)E/ρ = I/A

(3)

Put (3) in (2) we get,

Put (3) in (2) we get,E/ρ = e[ne Ve + nh vh]

Put (3) in (2) we get,E/ρ = e[ne Ve + nh vh]I/ò ρ = e / E[ne Ve + nh vh]

Put (3) in (2) we get,E/ρ = e[ne Ve + nh vh]I/ò ρ = e / E[ne Ve + nh vh]σ = e [ne Ve/E + nh vh/E]

(σ = Conductivity)

Here, mobility (m) = Drift vel./ Electric field

Here, mobility (m) = Drift vel./ Electric fieldσ = e [ne me + nh mh]

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