Question

Derive an expression for electric field due to uniformly charged infinite plane sheet by using gauss law
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Answer 1

Answer:

flux through a closed surface is equal to 1/ε0 times the net charge enclosed within the surface i.e., Let electric charge be uniformly distributed over the surface of a thin, non-conducting infinite sheet. Let the surface charge density (i.e., charge per unit surface area) be s. We have to calculate the electric field strength at any point distance r from the sheet of charge. Read more on Sarthaks.com - https://www.sarthaks.com/54371/state-gausss-electrostatic-derive-expression-electric-uniformly-charged-infinite-plane

Answer 2

Explanation:

please see the enclosed attachment for detailed explanation and step by step working.

take an infinitely large charged sheet MNOP of charge density sigma.

Take a point P at the centre of EFGH. To find E at P, construct a Gaussian surface - a cuboid IJKL - EFGH . The electric field and flux lines flow out of the sheet perpendicular to it.

Gauuss's law:

closed Integral over cuboid of E • dA = q/epsilon0.

2 E = sigma / epsilon0

E = sigma/(2 epsilon0