Question

Derive an expression for electric field intensity on perpendicular bisector of dipole and also explain its special case​

Answer 1

Answer:

Electric field due to an electric dipole at a point on its axial line: AB is an electric dipole of two point charges −q and +q separated by small distance 2d. P is a point along the axial line of the dipole at a distance r from the midpoint O of the electric dipole.