Question

derive an expression for equation of projectile and hence derive expressions for maximum height and horizontal range ​

Answer 1

Answer:

Trajectory of a projectile is a parabolic trajectory. ... During the derivation we found, if a projectile is thrown with sped 'u' and at an angle θ with the horizontal, y = x tanθ / ( 2 u^2 cosθ^2). During this video lecture we also discussed how a projectile motion is a combination of a vertical and a horizontal motion.