Question

derive an expression for gravitational potential​

Answer 1

Answer:

Expression for Gravitational Potential Energy at Height (h) – Derive ΔU = mgh. When, h<<R, then, R + h = R and g = GM/R2. ⇒ Note: The weight of a body at the centre of the earth is zero due to the fact that the value of g at the centre of the earth is zero.

Explanation:

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Answer 2

Answer:

U = 1/2 kx2.

g = acceleration (9.8 ms-2 on Earth)

W = m × g × h = mgh.

ΔU = GMm (1/ri – 1/rf) [ ri= initial position and rf= final position ]

If ri > rf then ΔU is negative.

ri = R and rf = R + h.

When, h<<R, then, R + h = R and g = GM/R2.

Explanation:

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