Question

derive an expression for heat exchanged in isochoric process ​

Answer 1

Answer:

The heat transferred to the system does work but also changes the internal energy of the system. In an isobaric process for a monatomic gas, heat and the temperature change satisfy the following equation: Q=52NkΔT Q = 5 2 N k Δ T . For a monatomic ideal gas, specific heat at constant pressure is 52R 5 2 R .

Explanation:

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