Question

derive an expression for heat produce in a conductor using joule' s law of heating​

Answer 1

Answer:

I=V/R. Heat generated per second, Heat. H=V×I×t.

Answer 2

Answer:

Here is your Answer

Explanation:

= I2Rt.

(b) (a) Electric fuse.

(b) Electric water heater.

(c) H = 100J , R = 4 Ω , t = 1 sec .

I2 = H / R.

= : Let 'V' be the potential difference applied across the two terminals of a resistor of resistance 'R' by a cell and 'I' be the current flowing through the resistor in time 't'. <br> ii. If charge Q flows through the resistor, then the electrical power 'P' is given by <br> `P=("Energy")/("time")" ...(1)"` <br> where, energy is the work done by cell to move charge Q across the resistor <br> `therefore" Energy " = VxxQ" ...(2)"` <br> `therefore" P"=(VQ)/(t)" ....[from equations (1) and (2)]"` <br> `=VI" ..."(because(Q)/(t)=I)" ....(3)"` <br> iii. The cell provides the energy to the resistor which is converted into heat energy, given by <br> `H=Pxxt=VxxIxxt" ...[from (3)](4)"` <br> iv. According to Ohm's law, <br> `V=IR" ...(5)"` <br> From equation (4) and (5), <br> `H=(V^(2)t)/(R) or H=I^(2)Rt` <br> This is called as Joule's law of heating