Derive an expression for horizontal range of a projectile fired at an angle
theta with velocity v on an inclined plane which makes an angle α with the horizontal
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the expression for this is
R = (u^2sin2Θ)/gcosα
here R is range of projectile
and it is not sin square theta it is a sin two theta
R = (u^2sin2Θ)/gcosα
here R is range of projectile
and it is not sin square theta it is a sin two theta
Answered by
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Answer:
2v^2 tan teta. sec teta / g
Explanation:
Attachments:
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