Question

Derive an expression for it for a body moving in uniform circular motion.
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Answer 1

Answer:

T=2πrv=2π(0.175m)5.0×106m/s=2.20×10−7s

ω=2πT=2π2.20×10−7s=2.856×107rad/s.

The position of the particle at t = 2.0 x 10−7 s with A = 0.175 m is

Explanation:

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Answer 2

Answer:

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