Derive an expression for Joule’s law of heating.
Give two examples for applications of heating effect of electric current
Answers
Answer:
Expression for joules law of heating is given below
The amount of work done when an electric charges, move against a potential difference which is denoted by V is given by;
W=V x Q …….. (1)
From the above expression,
V=W/Q
We know that,
V=IR …….. (2)
Q=It……… (3)
Therefore,
I=Q/t
Let us substitute (2) and (3) in (1) we get,
W=(IR)(It)
\mathrm{W}=\mathrm{l}^{2} \mathrm{RT}W=l
2
RT
W=H
Where H is the amount of heat produced, it is expressed in Joules J and I is expressed in terms of Ampere.
Therefore, \bold{\mathrm{H}=\mathrm{l}^{2} \mathrm{RT}}H=l
2
RT
Some of the examples of heating with the electric current are as follows:
1) Heaters
2) Geyser
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Answer:
W=V x Q …….. (1)
V=W/Q
V=IR …….. (2)
Q=It……… (3)
Therefore,
I=Q/t
Let us substitute (2) and (3) in (1) we get,
W=(IR)(It)
W=l
2
RT
W=H
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