Question

Derive an expression for K.E. of an object.Draw the diagram also.​

Answer 1

${\pink{\bf{Hola!!}}}$

Kinetic Energy=Work Done
KE=Force×Displacement.

[W=FS] [F=mg]
KE=mg×S

KE=mg${\frac{v^2-u^2}{2g}}$

KE=m${\frac{v^2-u^2}{2}}$

If u=0

KE=${\frac{1}{2}}$m(v²-0²)

$KE={\bf{\purple{\frac{1}{2}mv^2}}}$