Question

Derive an expression for kinetic energy of a body having mass m and moving with a velocity v. (b)When velocity of a body is increased 5 times, what is the change in its kinetic energy? ans quick plzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzzz its urgent

Answer 1

Answer:

Expression for K.E - KINETIC ENERGY-K.E = 1/2 mv2. "Energy posses by a body by virtue of its motion is referred to as 'Kinetic Energy'". Kinetic energy depends upon the mass and velocity of body. If velocity is zero then K.E. of body will also be zero.Kinetic energy is a scalar quantity like other forms of energies.

Consider a body of mass "m" starts moving from rest. After a time interval "t" its velocity becomes V.

If initial velocity of the body is Vi = 0 ,final velocity Vf = V and the displacement of body is "d". Then

Using equation of motion

2aS = Vf2 – Vi2

Putting the above mentioned values

2ad = V2 – 0

a = V2/2d

Now force is given by

F = ma

Putting the value of acceleration

F = m(V2/2d)

As we know that

Work done = Fd

Putting the value of F

Work done = (mv2/2d)(d)

Work done = mV2/2

OR

Work done = ½ mV2

Since the work done is motion is called "Kinetic Energy"

i.e.

K.E. = Work done

OR

K.E. =1/2mV2.

Answer 2

Answer:

Derive an expression for kinetic energy of a body having mass m and moving with a velocity v. ... (b) Kinetic energy is given by the expression KE = 1/2 mv^2, therefore, if velocity is made 5 times KE will increase by 25 times.