Question

derive an expression for magnetic field due to toride​

Answer 1

Explanation:

Length of toroid =2πr.

N= Number of turns in toroid =n(2πr) and current in one-turn =I.

∴ Current enclosed by circular pth =(n2πr). I.

(II) For points in the open space inside the toroid: No current flows through the Amperian loop. so I=0.

Magnetic moment of bar magnet =NIA

Answer 2

Answer:

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