Derive an expression for magnetic field produce due to flow pf current in straight wire
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When Current passes through a straight wire then a magnetic field is produced around that wire. Now, we find the expression for that magnetic field
Explanation:
Force on a single charge q moving with the drift velocity Vd is
Fs = qvdBsinθ
Force on N charges will be
Ft = N×qvdBsinθ
and N=nV where, “n” is charge per unit carrier and “V” is volume which is equal to “Al”. So,
Ft = (Aqnvd)lBsinθ
And
Aqnvd = I
So,
Ft = IlBsinθ
And,
B = Ft / Ilsinθ
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