Question

derive an expression for magnetic moment of a current loop as magnetic dipole , what is ampere cycle?​

Answer 1

Magnetic dipole moment of current loop is the product of current I and area A enclosed by the loop of current, i.e. where e is charge on electron, m is mass of electron, n denotes the number of orbit and h is Plack's constant.

Answer 2

Answer:

Magnetic moment of a revolving electron let the electron rotate about an axis with angular velocity w

Angular velcoity =wrod/s

w=2πf

frequency f=

2π

w

Hz

Rotating charge tends to induced current.

Equivalent current =qf=

2π

wq

Present case can be thought of as a current-carrying loop

Let the radius be a

then

A

=πa

2

n

^

n

^

- direction perpendicular to rotation

Magnetic moment =IA

=

2π

wq

×πa

2

=

2

wqa

2

for an electron q=e=1.6×10

−19

C

∴ Magnetic moment =

2

wea

2

Now,

given, N=300,D=14cm=14×10

−2

m,i=15A

Magnetic moment =NiA

=Ni

4

π

D

2

=300×10×

4

π

(14×10

−2

)

2

M=69.27Am

2