Question

Derive an expression for magnitude of magnetic dipole moment
of a revolving electron.​

Answer 1

Here's your answer

Here's your answerAn electron revolving around the nucleus possesses a dipole moment and the system acts like a tiny magnet. According to Bohr's model, the magnetic moment of an electron is μl = lπr2 = (evR)/2 here 'e' is an electron charge, 'v' is its speed in the orbit and 'r' is the corresponding radius of the orbit.

Here's your answerAn electron revolving around the nucleus possesses a dipole moment and the system acts like a tiny magnet. According to Bohr's model, the magnetic moment of an electron is μl = lπr2 = (evR)/2 here 'e' is an electron charge, 'v' is its speed in the orbit and 'r' is the corresponding radius of the orbit.Hope it helps you ❤️❤️ Please mark me as brainlist.

Answer 2

Answer:

Explanation:

Here's your answer

Here's your answerAn electron revolving around the nucleus possesses a dipole moment and the system acts like a tiny magnet. According to Bohr's model, the magnetic moment of an electron is μl = lπr2 = (evR)/2 here 'e' is an electron charge, 'v' is its speed in the orbit and 'r' is the corresponding radius of the orbit.

Here's your answerAn electron revolving around the nucleus possesses a dipole moment and the system acts like a tiny magnet. According to Bohr's model, the magnetic moment of an electron is μl = lπr2 = (evR)/2 here 'e' is an electron charge, 'v' is its speed in the orbit and 'r' is the corresponding radius of the orbit.Hope it helps you ❤️❤️ Please mark me as brainlist.