Question

Derive an expression for maximum efficiency of a single phase transformer.

Answer 1

Answer:

We know that,

Ƞ=output/output+losses.

Ƞ=V2I2cosф2/V2I2cosф2+W1+I22Ro2.

For maximum efficiency, dn/dI2=0.

Therefore W1=I22Ro2.

W1=I21Ro1.

I2(max. eff)=√(W1/R02)

V2I2(maxefficiency)=V2√W1/R02.

=V2I2√W1/IR2Ro2=V2I2√W1/Wai.