Question

Derive an expression for MI of a ring​

Answer 1

Answer:

The moment of inertia of a ring about of its diameter is given by Idia=I=21MR2 where R= radius of ring. Here, the distance between the tangent and the diameter is R. By parallel axis theorem, the moment of inertia about the tangent is. IT=Idia+MR2=I+2I=3I (as MR2=2I)

Answer 2

Answer:

The moment of inertia of a ring about of its diameter is given by Idia=I=21MR2 where R= radius of ring. Here, the distance between the tangent and the diameter is R. By parallel axis theorem, the moment of inertia about the tangent is. IT=Idia+MR2=I+2I=3I (as MR2=2I)

Explanation:

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