Question

derive an expression for minimum deviation for a prism​

Answer 1

Answer : -

A = Prism angle, δ = Angle of deviation, i1 = Angle of incidence, i2 = Angle of emergent.

• In the case of minimum deviation,∠r1 = ∠r2=∠r.
• A = ∠r1 + ∠r2
• A + δ = i1 + i2 (∵ In the case of minimum deviation.
• i1 = i2 = i and δ = δm)

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Answer 2

Answer:

A = Prism angle, δ = Angle of deviation, i1 = Angle of incidence, i2 = Angle of emergent.

In the case of minimum deviation,∠r1 = ∠r2=∠r.

A = ∠r1 + ∠r2

A + δ = i1 + i2 (∵ In the case of minimum deviation.

i1 = i2 = i and δ = δm)