Physics, asked by afreenpeerzade78, 6 months ago

derive an expression for potential energy​

Answers

Answered by nanditham1222
1

Answer:

Derivation for the equation of Potential Energy:

Let the work done on the object against gravity = W

               Work done, W = force × displacement

               Work done, W  = mg × h

               Work done, W = mgh

Since workdone on the object is equal to mgh, an energy equal  to mgh units is gained by the object . This is the potential energy (Ep) of the object.

                            Ep = mgh

Answered by saanvigrover2007
8

 \mathfrak{ Derivation \: of \: Potential \: Energy}

\mathsf{Things \: to \: know \: before\: Derivation}

 \mathsf{\implies Work \: done = Fs = F × height = \: Fh}

 \mathsf{\implies Work  = Energy}

 \mathsf{\implies Force = mass \: × \: acceleration \: = ma}

 \sf{\implies Acceleration \:due \:to \:gravity =\: 'g'}

 \mathsf{\implies Potential \: Energy \: is \: also \: written \: as \: E_p}

\mathsf{Derivation}

 \mathsf{\hookrightarrow E_p = Work done = Fs = Fh }

 \mathsf{\hookrightarrow E_p \: = \: Fh \: = ma × h }

 \mathsf{\hookrightarrow E_p\: = \:Fh \: = mg × h }

 \mathsf{\hookrightarrow E_p\: = \:mgh }

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