Physics, asked by abiknn24, 1 year ago

Derive an expression for potential energy.


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Answers

Answered by Rememberful
13

\textbf{Answer is in Attachment !}

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Answered by saanvigrover2007
38

 \mathfrak{ Derivation \: of \: Potential \: Energy}

\mathsf{Things \: to \: know \: before\: Derivation}

 \mathsf{\implies Work \: done = Fs = F × height = \: Fh}

 \mathsf{\implies Work  = Energy}

 \mathsf{\implies Force = mass \: × \: acceleration \: = ma}

 \sf{\implies Acceleration \:due \:to \:gravity =\: 'g'}

 \mathsf{\implies Potential \: Energy \: is \: also \: written \: as \: E_p}

\mathsf{Derivation}

 \mathsf{\hookrightarrow E_p = Work done = Fs = Fh }

 \mathsf{\hookrightarrow E_p \: = \: Fh \: = ma × h }

 \mathsf{\hookrightarrow E_p\: = \:Fh \: = mg × h }

 \mathsf{\hookrightarrow E_p\: = \:mgh }

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