Question

derive an expression for second order reaction​

Answer 1

Answer:

The order of the reaction is second, and the value of k is 0.0269 M-2s-1. Since the reaction order is second, the formula for t1/2 = k-1[A]o-1. This means that the half life of the reaction is 0.0259 seconds.

Explanation:

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Answer 2

Answer:

The differential rate law equation can be written as follows:

−d[R]dt=k[R]2

In order to obtain the integrated rate equation, this differential form must be rearranged as follows:

d[R][R]2=−kdt

Now, integrating on both sides in consideration of the change in the concentration of reactant between time 0 and time t, the following equation is attained.

∫[R]t[R]0d[R][R]2=−k∫t0dt

From the power rule of integration, we have:

∫dxx2=−1x+C

Where C is the constant of Integration. Now, using this power rule in the previous equation, the following equation can be attained.

1[R]t–1[R]0=kt

Which is the required integrated rate expression of second order reactions.