Derive an expression for terminal velocity of a body during a free-fall in a viscous
medium
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Answer:
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Explanation:
Terminal velocity: It is maximum constant velocity acquired by the body while falling freely in a viscous medium.
Terminal velocity: It is maximum constant velocity acquired by the body while falling freely in a viscous medium.When a small spherical body falls freely through a viscous medium, three forces act on it.
Terminal velocity: It is maximum constant velocity acquired by the body while falling freely in a viscous medium.When a small spherical body falls freely through a viscous medium, three forces act on it.(i) Weight of the body acting vertically downwards.
Terminal velocity: It is maximum constant velocity acquired by the body while falling freely in a viscous medium.When a small spherical body falls freely through a viscous medium, three forces act on it.(i) Weight of the body acting vertically downwards.(ii) Upward thrust due to buoyancy equal to weight of liquid displaced.
Terminal velocity: It is maximum constant velocity acquired by the body while falling freely in a viscous medium.When a small spherical body falls freely through a viscous medium, three forces act on it.(i) Weight of the body acting vertically downwards.(ii) Upward thrust due to buoyancy equal to weight of liquid displaced.Viscous drag acting in the direction opposite to the motion of body. According to Stoke's law, FXB, i.e., the opposing viscous drag goes on increasing with the increasing velocity of the body. 1
Terminal velocity: It is maximum constant velocity acquired by the body while falling freely in a viscous medium.When a small spherical body falls freely through a viscous medium, three forces act on it.(i) Weight of the body acting vertically downwards.(ii) Upward thrust due to buoyancy equal to weight of liquid displaced.Viscous drag acting in the direction opposite to the motion of body. According to Stoke's law, FXB, i.e., the opposing viscous drag goes on increasing with the increasing velocity of the body. 1As the body falls through a medium, its velocity goes on increasing due to ‘gravity. Therefore, the opposing viscous drag which acts upwards also goes on increasing. A stage reaches when the true weight of the body is just equal to the sum of the upward thrust due to buoyancy and the upward viscous drag. At this stage, there is no net force to accelerate the body. Hence it starts falling with a constant velocity, which is called terminal velocity. Let p be the density of the material of the spherical body of radius r and p0 be the density of the medium.
Terminal velocity: It is maximum constant velocity acquired by the body while falling freely in a viscous medium.When a small spherical body falls freely through a viscous medium, three forces act on it.(i) Weight of the body acting vertically downwards.(ii) Upward thrust due to buoyancy equal to weight of liquid displaced.Viscous drag acting in the direction opposite to the motion of body. According to Stoke's law, FXB, i.e., the opposing viscous drag goes on increasing with the increasing velocity of the body. 1As the body falls through a medium, its velocity goes on increasing due to ‘gravity. Therefore, the opposing viscous drag which acts upwards also goes on increasing. A stage reaches when the true weight of the body is just equal to the sum of the upward thrust due to buoyancy and the upward viscous drag. At this stage, there is no net force to accelerate the body. Hence it starts falling with a constant velocity, which is called terminal velocity. Let p be the density of the material of the spherical body of radius r and p0 be the density of the medium.True weight of the body,
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Answer:
Terminal velocity - your answer in the attachment
