Question

Derive an expression for terminal velocity of a sphere of radius a and density p(rho) falling through a viscous liquid of density σ .

Answer 1

Answer:

Force, F=10N

Mass, m=5Kg

Force,

F=ma

a=2m/s

2

Work done, W=F.ds

In first second, displacement,

s=

2

1

at

2

s=

2

1

×2×1

s=1m

So, work done,W=10×1=10J

In second second, s=

2

1

×2×4=4m

So, the displacement is , 4−1=3m

Hence, work done in 2 second is,

W=10×3

W=30J

Explanation:

sorry I no the correct answer and mark me brailest please pa