Question

Derive an expression for the current in a circuit with external resistance R when (a) n identical cells of emf E and internal resistance r are connected in series (b) m identical cells are connected in parallel

Answer 1

Answer:

The current in a circuit with external resistance r.= 1/r1 + 1/r2 + 1/rn

Explanation:

Step 1: A cell divides into two identical daughter cells after duplicating every component of it, including its chromosomes, during the mitotic process. The processes of mitosis are meticulously regulated by certain genes because this process is so crucial.

Step 2: The same current flows through a 4 ohm resistor when two identical cells are connected to it either in series or in parallel. The cell's internal resistance is. Not to worry!

Step 3: I = E/(R+r)

where I = current

E = emf

R = external resistance

r = total internal resistance

For resistors in series;

Total r = r1+r2+rn

For resistors in parallel

Total r.= 1/r1 + 1/r2 + 1/rn

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