Question

Derive an expression for the effect of height on acceleration due to gravity

Answer 1

$\huge\underline\mathfrak\purple{Solution}$

➡Acceleration due to gravity decreases with distance the accelerated object from the source of gravitational attraction.

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Answer 2

Answer:g°/g=1-2h/R

Explanation:

g=GM/R².

GM=R²g.....................1

g°=GM/(R+h)²

GM=(R+h)²g°.............2

from 1 and 2

R²g=(R+h)²g°

g°/g=R²/(R+h)²g°

=R²/{R(1+h/R)}²

g°/g=R²/R²(1+h/R)²

=1/1+h²/R²

=(1+h/R)-²

g°/g=1-2h/R