derive an expression for the electric field e due to adipole of length 2a at a pt distance 2a apart . deduce the expression for electric filed E due to the dipole at distance x from the centre of deploy on its axial line in term of deploy movement p. hence show that in the limite x >>a,E--> 2p /4πE0x³
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Electric field at point P at a distance r from centre of dipole due to +q
E
B
=
4πϵ
0
1
BP
2
q
along BP =
4πϵ
0
1
(r−a)
2
q
Electric field at point P due to -q is
E
A
=
4πϵ
0
1
AP
2
q
along PA =
4πϵ
0
1
(r+a)
2
q
Net field at P is given by
E
P
=E
B
−E
A
=
4πϵ
0
1
(
(r−a)
2
q
−
(r+a)
2
q
)=
4πϵ
0
q
(r
2
−a
2
)
2
4ar
=
4πϵ
0
1
(r
2
−a
2
)
2
2pr
along BP .
Where p is the dipole=2qa
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