Question

Derive an expression for the electric potential at any point along the axial line of an electric dipole. ??​

Answer 1

Answer:

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Explanation:

Suppose P is a point on the axial position of the dipole. Length of dipole = 2a

Suppose point P is at the distance 'r' from the center of the dipole.

We know that potential at a point is given as, V=14πε0.Qr

So, the potential at P due to q is, Vq=14πε0.qa+r

Potential at P due to –q is, V-q=14πε0.-qa-r

The total potential at P is,

V=Vq+V-q=14π∈0.q(a+r)+14π∈0.-q(r-a)=q4π∈0[1(a+r)+1(a-r)]V=q4π∈0.2a(a2-r2)

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