Physics, asked by garimamohindhru5492, 1 year ago

Derive an expression for the energy stored a parallel plate capacitor. On charging a parallel plate capacitor to a potential v, the spacing between the plates is halved, and dialect medium of = 10 is introduced between the plates, without disconnecting the

d.C. Source. Explain, using suitable expressions, how the (i) capacitance, (ii) electric field and (iii) energy density of the capacitor change.

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Answered by Anonymous
1

on charging a parallel plate capacitor to a potention 'V',the ... the plates, without disconnecting the dc souce explain with ... 2)energy density of the capacitor change.

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