derive an expression for the energy stored in a capacitor with Air as the medium between its plates.how does the stored energy change if Air is replaced by a medium of dielectric constant k
Answers
Answered by
1
Answer:
Explanation:
energy stored in the capacitor, change. Given, a parallel plate capacitor with air as dielectric is charged by d.c source. Later on, without disconnecting the source, air is replaced by another dielectric medium K. (i) Potential difference will remain constant as the capacitor remains connected to the battery.
Answered by
1
Answer:
(a) Derive the expression for the energy stored in a parallel plate capacitor. Hence obtain the expression for the energy density of the electric field.
(b) A fully charged parallel plate capacitor is connected across an uncharged identical
capacitor. Show that the energy stored in the combination is less than that stored initially in the single capacitor
Similar questions