Question

Derive an expression for the energy stored in a parallel plate capacitor with air
as the intervening medium. Air is now replaced by a dielectric medium of
dielectric constant K How does it change the energy and potential difference
of the capacitor if the capacitor remains connected to the battery?​

Answer 1

Answer:

(v) energy stored in the capacitor, change. Given, a parallel plate capacitor with air as dielectric is charged by d.c source. Later on, without disconnecting the source, air is replaced by another dielectric medium K. ... Therefore, the energy is increased by a factor of K.