Question

Derive an expression for the energy stored in a stretched wire

Answer 1

Explanation:

we know, energy stored in the stretched wire = workdone by force on it. this is the expression of energy stored in wire , where F is force applied on wire and x is extension of wire

Answer 2

Answer:

Heya

Hooke’s Law, F = -kx, where F is the force and x is the elongation.

The work done = energy stored in stretched string = F.dx

The energy stored can be found from integrating by substituting for force,

and we find,

The energy stored = kx2/2, where x is the final elongation.

The energy density = energy/volume

= (kx2/2)/(AL)

=1/2(kx/A)(x/L)

= 1/2(F/A)(x/L)

= 1/2(stress)(strain)