Question

Derive an expression for the equivalent resistences of three resistance connected in seriesl

Answer 1

0here is your answer......
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let consider the three resistance are connected in series

-----R1----R2-----R3--- and connected to potential difference v

since current is constant in series i= constant

so potential divides V=v1+v2+v3

since you know the formula v=IR
V1=IR1,V2=IR2.V3=IR3

V=V1+V2+V3
IR=IR1+IR2+IR3
IR=I(R1+R2+R3)
I GETS CANCELED

THEN R eff=R1+R2+R3


SO equivalent resistance R=R1+R2+R3

I HOPE YOU GOT YOUR ANSWER...

Answer 2

hope it will really help