Derive an expression for the force of interaction between two parallel wires carrying current. Use the expression to define S.I. unit of current.
Answers
Answered by
0
Let the distance between the two conductors carrying current I
1
and I
2
be d.
Magnetic field produced by conductor 1 at a distance d, B
1
=
4π
μ
o
d
2I
1
Force acting the conductor 2 placed in this magnetic field F=B
1
I
2
L
Thus we get F=
4π
μ
o
d
2I
1
I
2
L
Force er unit length of conductor 1 f=
4π
μ
o
d
2I
1
I
2
Now put d=1m, I
1
=I
2
=1A and L=1m
We get F=
2π
μ
2
=2×10
−7
N
Thus we define ampere as the current flowing in each conductor separated by a unit distance so that one conductor applies a force of 2×10
−7
N on a unit length of another parallel conductor.
Answered by
0
Parallel currents attract, antiparallel currents repel.
Attachments:
Similar questions