Question

derive an expression for the height of geo stationary satellite​

Answer 1

Answer:

Answer - h = 35889 km.

# Given - G = 6.67×10^-11 Nm^2/kg^2. M = 6 × 10^24 kg. R = 6400 km. T = 24 hrs = 86400 s.

# Solution - Time period of satellite is given by - T = 2π √(r^3/GM) T^2 = 4π^2.r^3/GM. r^3 = GM.T^2 / 4π^2. r^3 = 6.67×10^-11 × 6×10^24 × 86400^2 / 4×3.142^2. r^3 = 7.563×10^22. r = 4.229×10^7 m. r = 42289 km.