Physics, asked by Smeenu8247, 11 months ago

Derive an expression for the mass of the earth, given the orbital period of the
moon and the radius of its orbit.

Answers

Answered by abhi178
3

mass of the earth is given as M = 4π²r³/T²G .

Let mass of moon is m , mass of earth is M, radius of orbit is r and time period is T.

as we know, the moon is only one satellite of the earth which revolves around the earth in its orbit.

so, centripetal force = gravitational force

⇒mv²/r = GMm/r²

⇒v² = GM/r

for circular motion, v = ωr = (2π/T)r

then, (2πr/T)² = GM/r

⇒4π²r²/T² = GM/r

⇒ M = 4π²r³/T²G

hence, mass of the earth is given as M = 4π²r³/T²G

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Answered by Anonymous
1

\huge\bold\purple{Answer:-}

Let mass of moon is m , mass of earth is M, radius of orbit is r and time period is T.

as we know, the moon is only one satellite of the earth which revolves around the earth in its orbit.

so, centripetal force = gravitational force

⇒mv²/r = GMm/r²

⇒v² = GM/r

for circular motion, v = ωr = (2π/T)r

then, (2πr/T)² = GM/r

⇒4π²r²/T² = GM/r

⇒ M = 4π²r³/T²G

hence, mass of the earth is given as M = 4π²r³/T²G

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