Physics, asked by Smeenu8247, 1 year ago

Derive an expression for the mass of the earth, given the orbital period of the
moon and the radius of its orbit.

Answers

Answered by abhi178
3

mass of the earth is given as M = 4π²r³/T²G .

Let mass of moon is m , mass of earth is M, radius of orbit is r and time period is T.

as we know, the moon is only one satellite of the earth which revolves around the earth in its orbit.

so, centripetal force = gravitational force

⇒mv²/r = GMm/r²

⇒v² = GM/r

for circular motion, v = ωr = (2π/T)r

then, (2πr/T)² = GM/r

⇒4π²r²/T² = GM/r

⇒ M = 4π²r³/T²G

hence, mass of the earth is given as M = 4π²r³/T²G

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Answered by Anonymous
1

\huge\bold\purple{Answer:-}

Let mass of moon is m , mass of earth is M, radius of orbit is r and time period is T.

as we know, the moon is only one satellite of the earth which revolves around the earth in its orbit.

so, centripetal force = gravitational force

⇒mv²/r = GMm/r²

⇒v² = GM/r

for circular motion, v = ωr = (2π/T)r

then, (2πr/T)² = GM/r

⇒4π²r²/T² = GM/r

⇒ M = 4π²r³/T²G

hence, mass of the earth is given as M = 4π²r³/T²G

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