Derive an expression for the mass of the earth, given the orbital period of the
moon and the radius of its orbit.
Answers
mass of the earth is given as M = 4π²r³/T²G .
Let mass of moon is m , mass of earth is M, radius of orbit is r and time period is T.
as we know, the moon is only one satellite of the earth which revolves around the earth in its orbit.
so, centripetal force = gravitational force
⇒mv²/r = GMm/r²
⇒v² = GM/r
for circular motion, v = ωr = (2π/T)r
then, (2πr/T)² = GM/r
⇒4π²r²/T² = GM/r
⇒ M = 4π²r³/T²G
hence, mass of the earth is given as M = 4π²r³/T²G
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Let mass of moon is m , mass of earth is M, radius of orbit is r and time period is T.
as we know, the moon is only one satellite of the earth which revolves around the earth in its orbit.
so, centripetal force = gravitational force
⇒mv²/r = GMm/r²
⇒v² = GM/r
for circular motion, v = ωr = (2π/T)r
then, (2πr/T)² = GM/r
⇒4π²r²/T² = GM/r
⇒ M = 4π²r³/T²G
hence, mass of the earth is given as M = 4π²r³/T²G