Science, asked by nagashree9, 4 months ago

derive an expression for the maximum range of a projectile

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Answered by vanshika16310

1

Answer:

Let a projectile move with a velocity u which is inclined with the horizontal at angle of θ. The velocity after time 't' will be

v=vxi^+vyj^v=ucosθi^+(usinθ−gt)j^(Since:vy=usinθ−gt)

At maximum height the projectile will only have horizontal component that is

idk so i copied i am in grade 6 only

Answered by 8888ucpl49

0

Answer:

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