Physics, asked by kevalkhuti123456789, 6 months ago

Derive an expression for the moment of inertia of a thin uniform rod about an axis through its centre and perpendicular to

its length. Also determine the radius of gyration about the same axis.​

Answers

Answered by Anonymous
4

ꜰɪɢᴜʀᴇ 10.25 ᴄᴀʟᴄᴜʟᴀᴛɪᴏɴ ᴏꜰ ᴛʜᴇ ᴍᴏᴍᴇɴᴛ ᴏꜰ ɪɴᴇʀᴛɪᴀ ɪ ꜰᴏʀ ᴀ ᴜɴɪꜰᴏʀᴍ ᴛʜɪɴ ʀᴏᴅ ᴀʙᴏᴜᴛ ᴀɴ ᴀxɪꜱ ᴛʜʀᴏᴜɢʜ ᴛʜᴇ ᴄᴇɴᴛᴇʀ ᴏꜰ ᴛʜᴇ ʀᴏᴅ. λ=ᴍʟᴏʀᴍ=λʟ. λ = ᴍ ʟ ᴏʀ ᴍ = λ ʟ . ɪ=∫ʀ2ᴅᴍ=∫x2ᴅᴍ=∫x2λᴅx.

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Answered by SanehaSiddique
0

Answer:

the moment of inertia is denoted by I

and I = mr²

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